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CBSE Class 11-science Answered

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Asked by Prashant DIGHE | 06 Jun, 2020, 09:42: PM
answered-by-expert Expert Answer
Chemical reaction of dissociation of N2O4 can be written as-
 
left parenthesis straight a right parenthesis space straight N subscript 2 straight O subscript 4 space left right double arrow 2 NO subscript 2 increment straight G equals increment straight G subscript Reaction superscript straight o minus 2.303 RTlnQ subscript straight P straight Q subscript straight P equals fraction numerator straight p subscript NO subscript 2 end subscript superscript 2 over denominator straight p subscript straight N subscript 2 straight O subscript 4 end subscript end fraction equals fraction numerator left parenthesis begin display style 5 over 10 end style cross times 20 right parenthesis squared over denominator left parenthesis begin display style 5 over 10 end style cross times 20 right parenthesis end fraction equals space 10 space bar increment straight G subscript Reaction superscript straight o equals 2 increment straight G subscript NO subscript 2 end subscript minus increment straight G subscript straight N subscript 2 straight O subscript 4 end subscript space space space space space space space space space space space space space space space equals 2 cross times 50 minus 100 equals 0 increment straight G equals 0 minus 2.303 cross times 8.314 cross times 298 cross times log 10 space space space space equals negative 5705.8 space straight J left parenthesis straight b right parenthesis open parentheses straight P plus fraction numerator straight a over denominator straight V subscript straight m superscript 2 end fraction close parentheses open parentheses straight V subscript straight m minus straight b close parentheses equals RT space space space space space PV subscript straight m minus Pb plus straight a over straight V subscript straight m minus fraction numerator ab over denominator straight V subscript straight m superscript 2 end fraction equals RT space space space space space PV subscript straight m equals RT plus Pb minus straight a over straight V subscript straight m plus fraction numerator ab over denominator straight V subscript straight m superscript 2 end fraction space space space space space space space Intercept minus space space space space straight P equals 0 comma space space space straight V subscript infinity equals infinity PV subscript straight m equals RT plus Pb space space space space space space space space left parenthesis thin space Intercept minus RT comma space slope minus straight b right parenthesis
Answered by Ravi | 08 Jun, 2020, 02:19: PM

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