the pH of 0.1 M nh4cl is 5.12 find the hydrolysis constant degree of hydrolysis dissociation constant for base

Asked by rishika62124 | 3rd Mar, 2021, 05:02: AM

Expert Answer:

p H equals 7 minus 1 half p K subscript b minus 1 half log C
5.12 equals 7 minus 1 half pK subscript straight b space minus 1 half log 1 over 10
5.12 equals 7 minus 1 half p K subscript b minus 1 half left parenthesis negative 1 right parenthesis
5.12 equals 7 minus 1 half p K subscript b plus 1 half
1 half p K subscript b equals 7 minus 5.12 plus 0.5
1 half p K subscript b equals 2.38
p K subscript b equals 2.38 cross times 2 equals 4.76
K subscript b equals 57543.9

K subscript h equals K subscript w over K subscript b equals fraction numerator 10 to the power of negative 14 end exponent over denominator 57543.9 end fraction equals 1.737 cross times 10 to the power of negative 5 end exponent cross times 10 to the power of negative 14 end exponent equals 1.737 cross times 10 to the power of negative 19 end exponent
K subscript h equals end subscript C straight alpha squared
straight alpha equals square root of straight K subscript straight h over straight C end root equals square root of fraction numerator 1.737 cross times 10 to the power of negative 19 end exponent over denominator 0.1 end fraction end root equals square root of 1.737 cross times 10 to the power of negative 20 end exponent end root equals 1.317 cross times 10 to the power of negative 10 end exponent

Answered by Ravi | 16th Mar, 2021, 01:18: PM