question 54...chemical equilibrium... how to solve.... plz tell

Asked by veenatripathi | 28th May, 2020, 09:03: AM

Expert Answer:

Chemical equation-
 
straight A space space space space space space space space space space space plus space space space space space space space straight B space space space space space space space space left right double arrow space space space space space space space straight C space space space space plus space space space space space space space space space straight D
1 left parenthesis 1 minus straight x right parenthesis space space space space space space space space space 1 left parenthesis 1 minus straight x right parenthesis space space space space space space space space space space space space space straight x space space space space space space space space space space space space space space space space space straight x

straight K equals fraction numerator left square bracket straight C right square bracket left square bracket straight D right square bracket over denominator left square bracket straight A right square bracket left square bracket straight B right square bracket end fraction
straight K equals fraction numerator straight x cross times straight x over denominator left parenthesis 1 minus straight x right parenthesis left parenthesis 1 minus straight x right parenthesis end fraction

straight x equals 0.4 left parenthesis given right parenthesis

straight K equals fraction numerator 0.4 cross times 0.4 over denominator 0.6 cross times 0.6 end fraction equals 4 over 9

Answered by Ravi | 28th May, 2020, 09:10: PM