CBSE Class 11-science Answered
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Asked by ntg432000 | 26 Apr, 2019, 16:31: PM
Chemical equation of dissociation of NH3 can be written as
![space space space space space space space space space space space space space space space space space space space space space space space space space 2 NH subscript 3 space left right double arrow straight N subscript 2 plus 3 straight H subscript 2
space space space space Initially space space space space space space space space space space space space straight A space space space space space space space space space space 0 space space space space space space 0
space At space equilibrium space space space straight A left parenthesis 1 minus straight alpha right parenthesis space Aα over 2 space space fraction numerator 3 Aα over denominator 2 end fraction
percent sign space of space NH subscript 3 space by space volume equals space fraction numerator straight A left parenthesis 1 minus straight alpha right parenthesis over denominator space straight A left parenthesis 1 minus straight alpha right parenthesis plus space Aα over 2 plus space space fraction numerator 3 Aα over denominator 2 end fraction end fraction
space According space to space conditions comma
fraction numerator left parenthesis 1 minus straight alpha right parenthesis over denominator left parenthesis 1 plus straight alpha right parenthesis end fraction cross times 100 equals 20
straight alpha equals 2 over 3](https://images.topperlearning.com/topper/tinymce/cache/0622c35cd465cd2aac3b01f2d8aeffd2.png)
Answered by Ravi | 29 Apr, 2019, 15:58: PM
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