Pls answer the following

Asked by ntg432000 | 26th Apr, 2019, 04:31: PM

Expert Answer:

Chemical equation of dissociation of NH3 can be written as
space space space space space space space space space space space space space space space space space space space space space space space space space 2 NH subscript 3 space left right double arrow straight N subscript 2 plus 3 straight H subscript 2 space space space space Initially space space space space space space space space space space space space straight A space space space space space space space space space space 0 space space space space space space 0 space At space equilibrium space space space straight A left parenthesis 1 minus straight alpha right parenthesis space Aα over 2 space space fraction numerator 3 Aα over denominator 2 end fraction percent sign space of space NH subscript 3 space by space volume equals space fraction numerator straight A left parenthesis 1 minus straight alpha right parenthesis over denominator space straight A left parenthesis 1 minus straight alpha right parenthesis plus space Aα over 2 plus space space fraction numerator 3 Aα over denominator 2 end fraction end fraction space According space to space conditions comma fraction numerator left parenthesis 1 minus straight alpha right parenthesis over denominator left parenthesis 1 plus straight alpha right parenthesis end fraction cross times 100 equals 20 straight alpha equals 2 over 3

Answered by Ravi | 29th Apr, 2019, 03:58: PM

Related Videos

Dynamic Nature of Equilibrium - Part 1

This video explains the dynamic nature of equilibrium and the concept of eq...

Dynamic Nature of Equilibrium - Part 2

This video explains the dynamic nature of equilibrium.

Dynamic Nature of Equilibrium - Exam Decoded

This video contains practice questions on the dynamic nature of equilibrium...

All Questions Ask Doubt