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CBSE Class 10 Answered

On a plane at some distance from its base a mountain is found to have an elevation of 60°.At a station lying 900√3 further away from the mountain,the angle is reduced to 30°
Asked by vikasini.s | 01 Mar, 2019, 08:34: PM
answered-by-expert Expert Answer
Let x is the distance from mountain at location C where the angle of elevation of top of mountain is 60º.
 
At D which is away from C at a distance 900√3 m, let the angle of elevation of top of mountain is 30°.
 
we have,  tan 60 = (h/x) = √3   or   h  = x √3   .........................(1)
 
we have, tan 30 = [ h / (x+900√3) ] = 1/√3   or   h  = (x+900√3) / √3  .................(2)
 
from (1) and (2), we have ,     x √3 = (x+900√3) / √3     or   3x = x+900√3   or  x = 450√3  m
 
By substituting x in eqn.(1),   we get h = 450 m
Answered by Thiyagarajan K | 01 Mar, 2019, 11:28: PM

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