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CBSE Class 10 Answered

Amit, standing in a horizontal plane, finds a bird flying at a distance of 200m from him at an elevation of 30º. Deepak standing on the roof of 50m high building, finds the angle of elevation of the same bird to be 45º.Amot and Deepak are no opposite sidea of the bird. Find the distance of the bird form Deepak.
Asked by Ayushijoshi.ind | 08 Mar, 2019, 01:49: AM
answered-by-expert Expert Answer
Let Amit is standing at the bottom of the building at B and observing the bird at C with angle of elevation 30°.
It is assumed that given distance 200 m  is BC, the distance along line of sight.
 
we have,  sin 30 = CD/BC  = (1/2)   or   CD = (1/2) BC = 100 m
 
If Deepak is seeing the same bird at top of the building with angle of elevation 45°, we have , sin 45 = ( 1/√2 ) = CE/AC  
 
hence AC = CE √2  = (CD-DE)√2 = 50√2 ≈ 71 m
Answered by Thiyagarajan K | 08 Mar, 2019, 11:45: AM
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