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CBSE Class 11-science Answered

Two scaters of masses 40 kg and 60 kg stand facing each other at A and B resp.  such that AB=5cm . They pull on massless string streched between them where will the two meet??
Asked by ravikantmanchanda | 13 Mar, 2016, 01:18: PM
answered-by-expert Expert Answer
Let the centre of mass 'C' be at a distance x from 60 kg mass.
The distance of mass 40 kg is (5 - x)
Taking moments about C, we get
60x = (5 - x)40
60x = 200 - 40x
100x = 200
x = 2m
Thus they meet at the centre of mass i.e. at a distance of 2 m from mass 60 km and 3 m from 40 kg mass.
 
Note that the centre of mass is nearer to the heavier mass.
Answered by Yashvanti Jain | 13 Mar, 2016, 09:58: PM

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