what is the order of reaction if rate of reaction becomes 3 times and concentration of reaction becomes 9 times

Asked by manpreetkaur19971993 | 10th Jan, 2019, 07:06: AM

Expert Answer:

We know that,

Rate = K[Reatant]n

[Reactant] = a

Rate = r1

r1 = K[a]n

It is given that rate of reaction becomes 3 time, and concentration of reaction becomes 9 times

Therefore,

3 r1 = K[9a]n

1 third space equals space open parentheses 1 over 9 close parentheses to the power of straight n

therefore space straight n space equals space 2

The order of reaction is 2.

Answered by Varsha | 10th Jan, 2019, 11:13: AM

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