please solve it

Asked by rohitraman1115 | 22nd Jul, 2018, 08:27: PM

Expert Answer:

Volume space of space alkali space used space at space any space time space proportional to space mole space of space cids space present space at space that space time

At space space straight t space equals space 0 space space space

straight V subscript 0 space proportional to space mole space of space HCl

At space space straight t space equals straight t space

straight V subscript straight t space proportional to space mole space of space HCl plus space mole space of space CH subscript 3 COOCH subscript 3 space formed space at space straight t space equals 0

At space straight t space equals space infinity

straight V subscript infinity proportional to space mole space of space HCl plus space mole space of space CH subscript 3 COOCH subscript 3 space formed

therefore space straight a proportional to space straight V subscript infinity minus straight V subscript 0

At space space straight t space equals space 4500 space space sec

straight a equals open parentheses 47.15 minus 24.36 close parentheses

straight a equals 22.79

open parentheses straight a minus straight x close parentheses space equals straight V subscript infinity minus straight V subscript straight t
space
space space space space space space space space space space space equals 47.15 minus 29.32

open parentheses straight a minus straight x close parentheses space equals 17.83

straight K equals fraction numerator 2.303 over denominator straight t end fraction log open parentheses fraction numerator straight a over denominator open parentheses straight a minus straight x close parentheses end fraction close parentheses

space space equals fraction numerator 2.303 over denominator 4500 end fraction log open parentheses fraction numerator straight a over denominator open parentheses straight a minus straight x close parentheses end fraction close parentheses

straight K space equals 5.4 cross times 10 to the power of negative 5 end exponent space sec to the power of negative 1 end exponent

At space space space straight t space equals 7140 space sec

straight a space equals 47.15 minus 24.36

straight a equals space 22.79

open parentheses straight a minus straight x close parentheses space equals space 47.15 minus 31.72

open parentheses straight a minus straight x close parentheses space equals 15.43

straight K equals fraction numerator 2.303 over denominator 7140 end fraction log open parentheses fraction numerator 22.79 over denominator open parentheses 15.43 close parentheses end fraction close parentheses

straight K equals space 5.4 cross times 10 to the power of negative 5 end exponent space sec to the power of negative 1 end exponent




Half space life space space straight t subscript bevelled 1 half end subscript space equals fraction numerator 0.693 over denominator straight K end fraction

space space space space space space space space space space space space space space space space space space space space space equals fraction numerator 0.693 over denominator 5.4 cross times 10 to the power of negative 5 end exponent end fraction


space space Half space life space space straight t subscript bevelled 1 half end subscript space equals space 1.2 cross times 10 to the power of 5

Answered by Varsha | 23rd Jul, 2018, 03:12: PM

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