Request a call back

Three resistors of 10, 20 and 30 ohms are connected in parallel to a 9V battery. Calculate: ( a)Value of current through each resistor (b)Total current in the circuit (c)Total effective resistance of the circui
Asked by piyushmalik024 | 19 May, 2019, 11:31: AM
a) Current through each resistor:

For parallel combination of resistor, potential difference across each resistor is same.
Current through 10 Ω resistor is,

V = IR
V= 9V
R =10 Ω
Thus, I1 = 9/10 = 0.9 A

Current through 20 Ω resistor,
I2 = 9/20 = 0.45 A

Current through 30 Ω resistor is,
I3 = 9/30 = 0.3 A

b) Total current in the circuit is,

I = I1+ I2 + I3 = 0.9 + 0.3 + 0.45 = 1.65 A

Thus, total current flowing through the circuit is 1.65 A.

c) Effective resistance:

The resistors are connected in parallel,

Thus,

Thus, the effective resistance of the circuit is 5.45 Ω
Answered by Shiwani Sawant | 19 May, 2019, 03:03: PM
CBSE 10 - Physics
Asked by sakshikatewa0 | 08 Feb, 2024, 12:48: PM
CBSE 10 - Physics
Asked by kamalaranjanmohantymohanty5 | 06 Jan, 2024, 10:05: AM
CBSE 10 - Physics
Asked by nandhikasugumar | 05 Oct, 2023, 04:01: PM
CBSE 10 - Physics
Asked by daniya062008 | 02 Oct, 2023, 08:25: PM
CBSE 10 - Physics
Asked by prassanna.j | 03 Sep, 2023, 12:28: PM
CBSE 10 - Physics
Asked by prassanna.j | 03 Sep, 2023, 12:21: PM