CBSE Class 10 Answered
Three resistances each of 4 ohm are connected in the form of an equilateral triangle. What is the effective resistance between two corners of the triangle?
Asked by saradamahapatra9999 | 04 Mar, 2019, 15:43: PM
The resistances are connected in the form of an equilateral triangle. So, it is understood that the two resistors are in series and the third resistors with both its end connected to the other two resistors is in parallel to the two.
So for series combination of resistors,
Rs = 4 + 4 = 8 Ω
So this series combination is in parallel with the third resistor.
Thus, the effective resistance in the two corners of the triangle can be calculated using
![1 over R subscript p space equals space 1 over R subscript 1 plus 1 over R subscript 2
fraction numerator begin display style 1 end style over denominator begin display style R subscript p end style end fraction space equals space 1 over 8 plus 1 fourth space equals space 3 over 8
T h u s comma space R subscript p space equals space 8 over 3 space equals space 2.66 space capital omega](https://images.topperlearning.com/topper/tinymce/cache/ec9e2331b896c465dd5e6f782854144d.png)
Thus, the effective resistance between the two corners is 2.66 Ω
Answered by Shiwani Sawant | 04 Mar, 2019, 16:19: PM
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