substance X forms trimer when added to Benzene calculates the freezing point of the 0.25 molal solution. The degree of association of the solute is found to be 0.80. The freezing point of the benzene is 5.5oC and its Cryoscopic constant is 5.12 K m-1.
Asked by Topperlearning User | 4th Jun, 2014, 01:23: PM
initial number of moles 3 0
final number of moles m (1-α) mα/3
total number of moles after association = m (1-α) + mα/3 = m (1-2α/3)
= 0.25 (1-2x0.80/3)
ΔTf = Kf m
=5.12 x 0.177= 0.6
Tf (solution) = 278.65K-0.06K= 278.59K
Answered by | 4th Jun, 2014, 03:23: PM
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