Ask a Doubt
Request a call back

Join NOW to get access to exclusive study material for best results

CBSE Class 12-science Answered

substance X forms trimer when added to Benzene calculates the freezing point of the 0.25 molal solution. The degree of association of the solute is found to be 0.80. The freezing point of the benzene is 5.5oC and its Cryoscopic constant is 5.12 K m-1.
Asked by Topperlearning User | 04 Jun, 2014, 01:23: PM
answered-by-expert Expert Answer
                                              3X               X3
   initial number of moles       3                 0
   final number of moles        m (1-α)        mα/3
   total number of moles after association =     m (1-α) + mα/3    = m (1-2α/3)
                                                                 = 0.25 (1-2x0.80/3)
                                                                 = 0.177m
                                                                ΔTf = Kf m
                                                                        =5.12 x 0.177= 0.6

        Tf (solution) = 278.65K-0.06K= 278.59K

Answered by | 04 Jun, 2014, 03:23: PM

Concept Videos

Multiple Choice Questions Practice Test Subjective Questions Webinar Subjective Questions Pre Board Assessment
Answered Unanswered My Questions My Answers
CBSE 12-science - Chemistry
HOW TO FIND VANT OF FACTOR  
Asked by RAJAGUPTA | 01 Jan, 2020, 08:19: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 12-science - Chemistry
Solution
question image
Asked by brijk456 | 03 Sep, 2019, 12:07: AM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 12-science - Chemistry
Value of Van't Hoff factor if CH3COOH 60% dissociates and 40% dimerized is–(1) 1.2, (2) 1.4, (3) 1.6, (4) 1.8
Asked by patra04011965 | 18 Jul, 2019, 04:07: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 12-science - Chemistry
I know that answer is (a) but please explain the reason in detail
question image
Asked by govtsecschoolnayaganv051 | 16 Jun, 2019, 10:55: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 12-science - Chemistry
Calculate the freezing point of a solution containing 0.52 g glucose (C6H12O6) dissolved in 80.20g water. For water Kf = 1.86 K Kg mol-1
Asked by Topperlearning User | 04 Jun, 2014, 01:23: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 12-science - Chemistry
0.90 g of an  1:2 electrolyte was dissolved in 87.90 g of benzene. This raised the boiling point of benzene by 0.250 C. If the molecular mass of the electrolyte is 103.0molar calculate the molal elevation constant for benzene. Given that the solute dissociate with degree of dissociation 0.25.
Asked by Topperlearning User | 04 Jun, 2014, 01:23: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 12-science - Chemistry
0.216molal solution of Cadmium sulphate is prepared in 1000gram of water. The depression in freezing point was measured to be 0.284K. Calculate the Vant hoff factor. The Cryoscopic constant for water is 1.86K Kg mol-1.
Asked by Topperlearning User | 20 Jun, 2016, 03:50: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 12-science - Chemistry
Two molar solution of potassium Ferro cyanide has degree of dissociation 0.70 at 300K.Find out the osmotic pressure of the solution.
Asked by Topperlearning User | 04 Jun, 2014, 01:23: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 12-science - Chemistry
substance X forms trimer when added to Benzene calculates the freezing point of the 0.25 molal solution. The degree of association of the solute is found to be 0.80. The freezing point of the benzene is 5.5oC and its Cryoscopic constant is 5.12 K m-1.
Asked by Topperlearning User | 04 Jun, 2014, 01:23: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 12-science - Chemistry
Calculate the amount of KCl must be added to one kilogram of water so as to reduce its freezing point by two Kelvin. For water Kf = 1.86 K Kg mol-1.
Asked by Topperlearning User | 04 Jun, 2014, 01:23: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
My Class Videos Tests ₹ Plans Ask a Doubt

Be a Top Scorer in the Exam with Test Series and Test Generator!

Enrol Now
×