Asked by ritikabehera01 | 7th Mar, 2019, 09:28: AM
(a) From the ionisation energy point of view, we find that sum of first two ionisation energies (IE1+IE2) for Nickel is less than that of Pt, so the Ni(II) compounds will be more stable than Pt(II) compounds. Pt can also show a +4 oxidation state.
(b) Pt can form compounds of +4 oxidation state more easily as compared to Ni.
As the sum of the first four ionisation energies of Pt = IE1+IE2+IE3+IE4= 9.36 kJ/mol
(IE1+IE2+IE3+IE4)= 9.36 kJ/molis lesser than that of Ni (11.29 kJ/mol)
Answered by Ramandeep | 7th Mar, 2019, 11:36: AM
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