Request a call back

Join NOW to get access to exclusive study material for best results

CBSE Class 10 Answered

Q. Find the current drawn from the battery by the network of 4 resistors shown in the diagram. Kindly Refer the file uploaded for diagram.

 

 

Asked by Trisha Gupta | 09 Jun, 2021, 05:56: PM
Expert Answer

Resistance of the upper branch FCE are in series.
So, equivalent resistance in the branch FCE= R= 10 Ω + 10 Ω = 20 Ω
Resistance of lower branch FDE are in series
So, equivalent resistance in the branch FDE = R2 = 10 Ω + 10 Ω = 20 Ω
The two resistance R1 and R2 are parallel to each other.
If R is the equvalent resistance of network, then
begin mathsize 14px style 1 over straight R equals 1 over 20 plus 1 over 20 equals 2 over 20 equals 1 over 10 end style
or R = 10 Ω
Current, V = IR

begin mathsize 14px style straight I equals straight V over straight R equals fraction numerator 3 space straight V over denominator 10 space straight capital omega end fraction equals 0.3 space straight A end style 
 

Answered by Shiwani Sawant | 09 Jun, 2021, 09:34: PM
CBSE 10 - Physics
Asked by priyatinsola02 | 20 Mar, 2022, 11:26: PM
ANSWERED BY EXPERT
CBSE 10 - Physics
Asked by topperlearningforcontent | 23 Feb, 2022, 11:34: AM
ANSWERED BY EXPERT
CBSE 10 - Physics
Asked by tanyajain164 | 22 Jan, 2022, 09:44: AM
ANSWERED BY EXPERT
CBSE 10 - Physics
Asked by megha.chhoti1456 | 02 Aug, 2021, 08:53: PM
ANSWERED BY EXPERT
CBSE 10 - Physics
Asked by deep.saluja101 | 10 Mar, 2021, 10:07: PM
ANSWERED BY EXPERT
CBSE 10 - Physics
Asked by abhinavpandey7345 | 04 Dec, 2020, 07:12: AM
ANSWERED BY EXPERT
CBSE 10 - Physics
Asked by acshanadhana15 | 18 Oct, 2020, 07:21: PM
ANSWERED BY EXPERT

Start your hassle free Education Franchisee and grow your business!

Know more
×