Asked by narinder | 1st Nov, 2010, 11:58: PM
Velocity of efflux of a liquid through an orifice is equal to the velocity which a body would attain in free falling from surface of liquid to the orifice.
Let the height of the hole from the surface of the liquid be 'h' ; then
velocity of efflux, v = ( 2gh)1/2 ; which only depends on the factor 'h'.
Now, in the given question 'h' is same for both the liquids;
hence the ratio of velocity of efflux of water to that of mercury will be 1:1.
Horizontal range of the liquid on the table , H = 2 [( H - h) ( h) ]1/2 .
Here, H = total height of the liquid column.
hence both the jets will fall at the same distance on the table.
We hope this clarifies your doubt.
Answered by | 2nd Nov, 2010, 07:23: PM
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