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(ii) A Liquid of 10 litres with Relative density of 1.80 is mixed with 8 litres of a liquid of Relative density 0.80. If the bulk of the liqui shrinks one percent on mixing, calculate the relative density, Asked by suragimathpraveen2001 | 10 Jan, 2022, 08:06: PM Expert Answer
Mass of liquid-1 = volume × density =  ( 10 × 10-3 m3 ) × ( 1.80 × 103 kg m-3 ) = 18 kg

Mass of liquid-2 =  ( 8 × 10-3 m3 ) × ( 0.80 × 103 kg m-3 ) = 6.4  kg

Total mass of mixture = ( 18.0 + 6.4 )  kg = 24.4  kg

Volume of mixture = ( 10 + 8 ) × 0.9 L = 16.2 L

Density of mixture = mass / volume = ( 24.4 kg ) / ( 16.2 × 10-3 m3 )  = 1.506 × 103 kg/m3

Relative density = density / density of water = 1.506 × 103 / 103  = 1.506
Answered by Thiyagarajan K | 10 Jan, 2022, 10:06: PM
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