Request a call back

Please solve the question. I can't understand how to solve this problem
Asked by raghuvanshisaumya461 | 03 Dec, 2021, 08:05: AM
Change in Pressure Δp  , when force is applied to piston connected to small syringe is calculated as

Δp = force /area  = 10 N / [ π ( 0.5 × 0.5 ) × 10-4 ] m2  = 1.273 × 105 Pa

Since pressure change is same in all the point , Force experienced by piston connected to bigger syringe is calculated as

Force = pressure × area =  1.273 × 105 Pa × π ( 1.5 × 1.5 ) × 10-4  m2 = 90 N

------------------------------------------------------------

Change in volume in small syringe , ΔV  = Area × distance moved by piston

Change in volume in small syringe , ΔV  = π ( 0.5 × 0.5 ) × 10-4 × 0.06 = 4.712 × 10-6 m3

Expanded volume in bigger springe will be same as ΔV

Distance moved out by piston , d = ΔV / Area  = 4.712            × 10 m / -63π ( 1.5 × 1.5 )   m× 10-42

Distance moved out by piston , d = 0.667 cm
Answered by Thiyagarajan K | 03 Dec, 2021, 09:34: AM

## Concept Videos

CBSE 11-science - Physics
Asked by arjunsah797 | 12 Mar, 2022, 11:10: AM
CBSE 11-science - Physics
Asked by raghuvanshisaumya461 | 03 Dec, 2021, 08:05: AM
CBSE 11-science - Physics
Asked by abhinavakrishna1009 | 31 Mar, 2021, 11:15: AM
CBSE 11-science - Physics
Asked by ashanihalchandani | 26 May, 2020, 09:11: AM
CBSE 11-science - Physics
Asked by Limalcr043 | 03 Jul, 2019, 06:28: PM
CBSE 11-science - Physics
Asked by rushabhjain.a | 09 Mar, 2019, 12:31: PM