Please solve the question. I can't understand how to solve this problem

Asked by raghuvanshisaumya461 | 3rd Dec, 2021, 08:05: AM

Expert Answer:

Change in Pressure Δp  , when force is applied to piston connected to small syringe is calculated as
 
Δp = force /area  = 10 N / [ π ( 0.5 × 0.5 ) × 10-4 ] m2  = 1.273 × 105 Pa 
 
Since pressure change is same in all the point , Force experienced by piston connected to bigger syringe is calculated as
 
Force = pressure × area =  1.273 × 105 Pa × π ( 1.5 × 1.5 ) × 10-4  m2 = 90 N
 
 
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Change in volume in small syringe , ΔV  = Area × distance moved by piston
 
Change in volume in small syringe , ΔV  = π ( 0.5 × 0.5 ) × 10-4 × 0.06 = 4.712 × 10-6 m3
 
Expanded volume in bigger springe will be same as ΔV
 
Distance moved out by piston , d = ΔV / Area  = 4.712            × 10 m / -63π ( 1.5 × 1.5 )   m× 10-42
 
Distance moved out by piston , d = 0.667 cm

Answered by Thiyagarajan K | 3rd Dec, 2021, 09:34: AM