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CBSE Class 11-science Answered

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Asked by ankurgoyal616 | 27 Sep, 2022, 03:07: PM
answered-by-expert Expert Answer
 
Gravitational attraction force between the two masses provides the necessary centripetal force to go in a circular path of radius R .
 
 
Gravitational force of attraction = begin mathsize 14px style G space cross times m squared over left parenthesis 2 R right parenthesis squared space equals space G space cross times fraction numerator m squared over denominator 4 space R squared end fraction end style
where G is gravitation universal constant and m is mass of each particle.
 
Centripetal force = m ( v2 / R )
 
begin mathsize 14px style m space cross times v squared over R space equals space G space cross times fraction numerator m squared over denominator 4 R squared end fraction end style
From above expression we get
 
begin mathsize 14px style v space equals space 1 half square root of fraction numerator G space m over denominator R end fraction end root end style
Answered by Thiyagarajan K | 27 Sep, 2022, 08:58: PM

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