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It's the same question printed in the next page so I combined it

Asked by prakriti12oct | 1st Jun, 2020, 10:29: PM

Expert Answer:

Suppose, Partial pressure of B and D are p₁ atm of each.

Partial pressure of E and D due to dissociation of C are p₂ atm of each.

$straight A left parenthesis straight s right parenthesis left right double arrow straight B left parenthesis straight g right parenthesis plus straight D left parenthesis straight g right parenthesis space space straight C left parenthesis straight s right parenthesis left right double arrow straight E left parenthesis straight g right parenthesis plus straight D left parenthesis straight g right parenthesis straight k subscript straight p subscript 1 end subscript equals straight p subscript straight B. space straight p subscript straight D equals straight p subscript 1 left parenthesis straight p subscript 1 plus straight p subscript 2 right parenthesis equals 400 space space space..... left parenthesis 1 right parenthesis straight K subscript straight p subscript 2 end subscript equals straight p subscript straight E. straight p subscript straight D equals straight p subscript 2 left parenthesis straight p subscript 1 plus straight p subscript 2 right parenthesis equals 900 space....... left parenthesis 2 right parenthesis straight p subscript 1 equals 11.097 atm space space and space straight p subscript 2 equals 24.96 space atm Pressure space over space solid space mixture equals 2 left parenthesis straight p subscript 1 plus straight p subscript 2 right parenthesis equals 2 left parenthesis 11.097 plus 24.96 right parenthesis equals 72.114 space atm$

Answered by Ravi | 3rd Jun, 2020, 11:39: AM

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