numerical question

Asked by  | 25th Jun, 2008, 05:17: PM

Expert Answer:

Let the initial velocity be u.

Now v=u-gt,

For maximum height,

v=0,or t=u/g

and H=u2/2g

Time to reach height h,t'=u/3g

so h=ut-(1/2)gt2=u2/3g-(1/2)g(u2/9g2)=5/18 u2/g


Answered by  | 6th Aug, 2008, 07:13: PM

Queries asked on Sunday & after 7pm from Monday to Saturday will be answered after 12pm the next working day.