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CBSE Class 11-science Answered

numerical question
Asked by | 25 Jun, 2008, 05:17: PM
answered-by-expert Expert Answer

Let the initial velocity be u.

Now v=u-gt,

For maximum height,

v=0,or t=u/g

and H=u2/2g

Time to reach height h,t'=u/3g

so h=ut-(1/2)gt2=u2/3g-(1/2)g(u2/9g2)=5/18 u2/g

h/H=5:9

Answered by | 06 Aug, 2008, 07:13: PM

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