NUMERICAL QUESTION BASED ON THE MOTION UNDER GRAVITY

Asked by  | 4th Dec, 2008, 03:06: PM

Expert Answer:

Let height of tower be h.

All quantities in the downward direction are assumed to be negative, and in the upward direction are positive.

The stone rises from the top of the tower, reaches a maximum height and then falls back again. So the distance through which it actually falls is -h.

u = 5m/s ; t = 5s; s =-h;

s=ut +1/2at^2

-h = 5t + 1/2(10)t^2

-h = 5(5) + 1/2(10)5^2

-h =25 +125 = 150

height of the tower is 150m

Answered by  | 6th Dec, 2008, 10:55: AM

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