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Judge the equivalent resistance when the following are connected in parallel - (a) 1 Ω and 106Ω, (b) 1Ω and 103Ω and 106Ω. can you please answer this question fast.
Asked by swatipuspapatel | 21 Feb, 2022, 07:35: PM
answered-by-expert Expert Answer
When 
a) 1Ω and 106 Ω are in parallel
1 over R subscript P equals space 1 over R subscript 1 plus 1 over R subscript 2 space equals space 1 over 1 plus 1 over 106 equals space 107 over 106 equals 1.009 capital omega 
Thus,equivalent resistance in the above case is 1.009 Ω 
 
b) 1Ω and 103Ω and 106Ω 
1 over R subscript P equals 1 over R subscript 1 plus 1 over R subscript 2 plus 1 over R subscript 3 equals space 1 over 1 plus 1 over 103 plus 1 over 106 equals 104 over 103 plus 1 over 106 equals 207 over 10918 capital omega equals 0.018 capital omega 
 
Please note that you can keep the values in fractional form instead of decimal form. 
Answered by Shiwani Sawant | 22 Feb, 2022, 09:20: AM

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