Asked by tamanpreets46 | 3rd May, 2020, 03:36: PM

Expert Answer:

Check dimensional correctness of 
1/2 mv2 = mgh 
 
Solution :- 
L.H.S = 1/2 mv2 
 
Dimension of m is [M]
Dimension of v is [ LT-1]
Thus, dimension of v2 is [L2T-2]
 
Thus, dimension of LHS is = [ML2T-2]  ....(1)
 
RHS = mgh 
Dimension of m is [M]
Dimension of g = [LT-2]
Dimension of h = [L]
Thus, dimension of RHS = [ML2T-2] .....(2)
 
Thus, from (1) and (2), 
LHS =RHS
 
Hence, the given equation is dimensionally correct. 

Answered by Shiwani Sawant | 3rd May, 2020, 07:20: PM