CBSE Class 11-science Answered
frequency of vibration (n) of a stretched string depends on its length (l) , tension (t) and linear mass density taking proportionality constant k=½ find a relation between them
Asked by ss4172380 | 14 Nov, 2023, 08:05: AM
Expert Answer
Let Frequency n la , where l is length of string and a is number .
Let Frequency n Tb , where T is tension force and b is number .
Let Frequency n mc , where m is linear mass density and c is number .
Hence we can write Frequency n as
n = k × l a × T b × m c .................... (1)
where k = 1/2 is proportionality constant .
Let M , L , T be the dimension symbol for mass, length and time respectively
Dimension of frequency = T-1
Dimension of length = M
Dimension of tension force = M L T-1/2
Dimension of linear mass density = mass / length = M L-1
Hence , if we apply dimensions to eqn.(1) , we get
By equating the respective exponents on both sides, we get
a + b - c = 0
b + c = 0
-2b = -1
By solving above equations , we get , a = -1 , b = 1/2 , c = -1/2
Hence , we rewrite eqn.(1) as
Answered by Thiyagarajan K | 14 Nov, 2023, 09:18: AM
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