Asked by sonali | 25th Apr, 2012, 09:49: AM
The general equation of the line with a and b as x and y intercepts respectively is x/a + y/b = 1.
Now, it is given that the line makes positive equal intercepts on axes. Let the equal intercepts be p.
So, the equation of line is x/p + y/p = 1 or x + y = p.
Now, it is given that the line passes through (3, 2). Putting, x = 3 and y = 2 in the equation, we get p = 5.
Thus, the equation of the required line is x + y = 5.
Answered by | 25th Apr, 2012, 06:15: PM
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