exercise 12 b q 8 (eq. of a straight line)
Asked by nilesh.dhote74 | 17th May, 2020, 10:00: PM
The equation of a line is 2x + 3y = 6 ... (1)
and it intesects the y - axis at A.
So, the coordinates of A(0, y).
From (1), 2(0) + 3y = 6 → 3y = 6 → y = 2.
(i) The coordinates of A are (0, 6).
(ii) The required line is perpendicular to the given line.
From (1), 3y = -2x + 6 → y = (-2/3)x + 2
Slop of required line = 3/2
By Point - slope form, Equation of required line is
y - 6 = 3/2(x - 0)
→ y - 6 = (3/2)x
→ 2y - 12 = 3x
→ 3x - 2y = -12
Answered by Yasmeen Khan | 17th May, 2020, 11:57: PM
- a straight line makes on the coordinate axes positive intercepts whose sum is 5.if the line passes through P(-3,4),find its equations
- find the equation of a line having inclination 60 and making an intercept of -1/3 on y axis
- Q. 37
- Q5 a part
- Write the equation of perpendicular bisector of line joining A(4,2) and B(-3,-5)
- Find the equations of the diagonal of a rectangle whose sides are x+1=0,x-4=0,y+1=0 and y-2=0.
- Plz explain the step highlighted Why are they added and why the sum is equal to1
Kindly Sign up for a personalised experience
- Ask Study Doubts
- Sample Papers
- Past Year Papers
- Textbook Solutions
Verify mobile number
Enter the OTP sent to your number