ex. 12 b question 15
Asked by nilesh.dhote74 | 18th May, 2020, 09:22: PM
Question: Find the equation of a line parallel to BC and passes through the centroid of triangle ABC where A=(-1, 4), B=(6, 2) and C=(4, 6).
Centroid of triangle ABC = (-1+6+4/3, 4+2+6/3) = (9/3, 12/3) = (3, 4)
Slope of line BC = 6-2/4-6 = 4/-2 = -2
Slope of line parallel to BC = -2
Therefore, equation of line parallel to BC and passing through the centroid of triangle ABC is given by
y-4 = -2(x-3)
y-4 = -2x+3
Answered by Renu Varma | 19th May, 2020, 10:29: AM
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