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Asked by Kanwaranita10 | 3rd Mar, 2020, 02:48: PM

Expert Answer:

The lines are 
5x-3y+2=0 ... (i)
6x-py+7=0 ... (ii)
F r o m space left parenthesis i right parenthesis space rightwards double arrow space y equals fraction numerator 5 x plus 2 over denominator 3 end fraction equals 5 over 3 x plus 2 over 3 space space w h i c h space i s space o f space t h e space f o r m space y equals m x plus c
T h e r e f o r e comma space s l o p e space o f space left parenthesis i right parenthesis space i s space 5 over 3
S i m i l a r l y comma space s l o p e space o f space l i n e space left parenthesis i i right parenthesis space i s space 6 over p
S l o p e space o f space t w o space p e r p e n d i c u l a r space l i n e s space i s space minus 1
therefore 5 over 3 cross times 6 over p equals negative 1
therefore p equals negative 10
therefore space left parenthesis i i right parenthesis space b e c o m e s space 6 x plus 10 y plus 7 equals 0
T h e space l i n e space p a r a l l e l space t o space left parenthesis i i right parenthesis space w i l l space b e space o f space t h e space f o r m space 6 x plus 10 y plus k equals 0 space... space left parenthesis i i i right parenthesis
S i n c e space left parenthesis i i i right parenthesis space p a s s e s space t h r o u g h space left parenthesis negative 2 comma negative 1 right parenthesis
therefore left parenthesis negative 2 comma negative 1 right parenthesis space s a t i s f i e s space left parenthesis i i i right parenthesis
rightwards double arrow negative 12 minus 10 plus k equals 0
rightwards double arrow k equals 22
therefore space T h e space r e q u i r e d space l i n e space i s space 6 x plus 10 y plus 22 equals 0

Answered by Renu Varma | 3rd Mar, 2020, 04:42: PM