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ex. 12 A q3
Asked by nilesh.dhote74 | 07 May, 2020, 10:22: PM
To find the slope of a line perpendicular to AB if
(i) A(-4, 2) and B(5, 8)
(ii) A(-1, 6) and B(3, -2)
(iii) A(5, -3) and B(7, 3)
Solution:
(i)
Slope of AB = (y2-y1)/(x2-x1) = (8-2)/[5-(-4)] = 6/9 = 2/3
Slope of a line perpendicular to AB = -1/Slope of AB = -1/(2/3) = -3/2

(ii)
Slope of AB = (y2-y1)/(x2-x1) = (-2-6)/[3-(-1)] = -8/4 = -2
Slope of a line perpendicular to AB = -1/Slope of AB = 1/2

(iii)
Slope of AB = (y2-y1)/(x2-x1) = [3-(-3)]/[7-5] = 6/2 = 3
Slope of a line perpendicular to AB = -1/Slope of AB = -1/3
Answered by Renu Varma | 08 May, 2020, 11:49: AM

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