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exercise 12 b 9 (equation of a straight line
Asked by nilesh.dhote74 | 17 May, 2020, 10:09: PM
Question: Find the equation of the lines passing through the point (4, 0) and equally inclined to the coordinate axes.
Solution:
(i)
Since the line is equally inclined to the coordinate axes and it is in the first quadrant, angle of inclination is 45o
Slope of line is m = tan 45o = 1
Also, the line passes through the point (4, 0)
Therefore, equation of line will be
y - 0 = m(x - 4)
y = x - 4
x - y = 4

(ii)
Since the line is equally inclined to the coordinate axes and it is in the fourth quadrant, angle of inclination is -45o
Slope of line is m = tan(-45o) = -1
Also, the line passes through the point (4, 0)
Therefore, equation of line will be
y - 0 = m(x - 4)
y = -(x - 4)
x + y = 4
Answered by Renu Varma | 18 May, 2020, 10:00: AM
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