if NaCl is doped with 10% of SrCl2.calculate the concentration of cation vacancies?

Asked by devna | 19th Jan, 2012, 08:04: PM

Expert Answer:

One cation of SrCl2 would create one cation vacancy in NaCl crystal. Therefore, number of cation vacancies created in the lattice of NaCl is equal to the number of divalent Sr2+ ions added.

Therefore, Concentration of cation vacancy on being doped with 10 mol % of SrCl2 = 0.1 mol

Number of Sr2+ ions in this amount =0.1 x 6.023 x 1023 Sr2+ ions

Number of cation vacancies = 6.023 X 1022

Answered by  | 20th Jan, 2012, 05:53: PM

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