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In diamond C atoms occupy FCC lattice points as well as alternate tetrahedral voids the edge length of unit of unit cell is 356.7pm.Calculate the closest distances between C atom and the fraction of total volume occupies by C atom.
Asked by sardaarjii2012 | 31 Oct, 2021, 09:05: PM
answered-by-expert Expert Answer
For space diamond space unit space cell space equals space fraction numerator square root of 3 over denominator 4 end fraction straight a space equals space 2 straight r Here space straight a space is space the space edge space length space and space straight r space is space the space radius space of space straight C space atom. space space straight a equals 356 space pm Hence comma space fraction numerator square root of 3 over denominator 4 end fraction cross times 356 space equals space 2 straight r straight D equals space 2 straight r straight D space equals space 89 square root of 3 straight D equals 1.7320 cross times 89 straight D space equals space 154.15
Answered by Ramandeep | 01 Nov, 2021, 12:41: PM

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CBSE 12-science - Chemistry
In diamond C atoms occupy FCC lattice points as well as alternate tetrahedral voids the edge length of unit of unit cell is 356.7pm.Calculate the closest distances between C atom and the fraction of total volume occupies by C atom.
Asked by sardaarjii2012 | 31 Oct, 2021, 09:05: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 12-science - Chemistry
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