In diamond C atoms occupy FCC lattice points as well as alternate tetrahedral voids the edge length of unit of unit cell is 356.7pm.Calculate the closest distances between C atom and the fraction of total volume occupies by C atom.

Asked by sardaarjii2012 | 31st Oct, 2021, 09:05: PM

Expert Answer:

For space diamond space unit space cell space equals space fraction numerator square root of 3 over denominator 4 end fraction straight a space equals space 2 straight r
Here space straight a space is space the space edge space length space and space straight r space is space the space radius space of space straight C space atom. space space straight a equals 356 space pm

Hence comma space fraction numerator square root of 3 over denominator 4 end fraction cross times 356 space equals space 2 straight r
straight D equals space 2 straight r

straight D space equals space 89 square root of 3

straight D equals 1.7320 cross times 89

straight D space equals space 154.15

Answered by Ramandeep | 1st Nov, 2021, 12:41: PM