CBSE Class 10 Answered
If A and B are roots x^2 - 6x + 4 = 0 then find the value of [(A-2)^16 + (B-6)^8]÷A^8.
Asked by acv27joy | 10 Dec, 2018, 01:16: PM
Expert Answer
Answered by Thiyagarajan K | 13 Dec, 2018, 06:45: AM
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