# how to calculate the resistance if the resistors are inclined between parallel wires

### Asked by acshanadhana15 | 18th Oct, 2020, 07:21: PM

Expert Answer:

###
For such problems,
We will start solving from right side.
In circuit diagram,
R_{8} and R_{10} are in series with each other while R_{9} is in parallel to them
Thus,
R_{s} = 10 + 2 = 12 Ω
and
1/Rp = (1/ R_{s}) + (1/R_{9}) = (1/12) + (1/6)
Thus,
R_{p} = 4 Ω
Let this combination of resistors R_{8}, R_{9} and R_{10} be named as R_{a}
The resistor R_{7} is in resistor with R_{a}
Thus,
R_{a} + R_{7 }= 4 + 8 = 12 Ω
R_{6} is in parallel to this whole combination and let us name this whole combination as R_{b}
Thus,
1/R_{b} = (1/R_{6}) + (1/12) = (1/6) + (1/12)
R_{b} = 4 Ω
From circuit diagram
R_{b} ad R_{5} is in series,
Thus,
R_{b} + R_{5} = 4 + 4 = 8 Ω
R_{4} is in paralell to this combination and let the resistance be R_{c}
Thus,
1/R_{c} = (1/8) + (1/ 8)
R_{c} = 4 Ω
R_{c} and R_{3} are in series
Thus,
R_{c} + R_{3} = 4 + 4 = 8 Ω
This 8 ohms is in parallel with R_{2} and can be named as R_{d }
Thus,
1/R_{d }= (1/8) + (1/R_{2}) = (1/8) + (1/8)
R_{d} = 4 Ω
R_{d }is in series with R_{1}
Thus,
R_{eq} = R_{d} + R_{1} = 4 + 6 = 10 Ω

For such problems,

We will start solving from right side.

In circuit diagram,

R

_{8}and R_{10}are in series with each other while R_{9}is in parallel to themThus,

R

_{s}= 10 + 2 = 12 Ωand

1/Rp = (1/ R

_{s}) + (1/R_{9}) = (1/12) + (1/6)Thus,

R

_{p}= 4 ΩLet this combination of resistors R

_{8}, R_{9}and R_{10}be named as R_{a}The resistor R

_{7}is in resistor with R_{a}Thus,

R

_{a}+ R_{7 }= 4 + 8 = 12 ΩR

_{6}is in parallel to this whole combination and let us name this whole combination as R_{b}Thus,

1/R

_{b}= (1/R_{6}) + (1/12) = (1/6) + (1/12)R

_{b}= 4 ΩFrom circuit diagram

R

_{b}ad R_{5}is in series,Thus,

R

_{b}+ R_{5}= 4 + 4 = 8 ΩR

_{4}is in paralell to this combination and let the resistance be R_{c}Thus,

1/R

_{c}= (1/8) + (1/ 8)R

_{c}= 4 ΩR

_{c}and R_{3}are in seriesThus,

R

_{c}+ R_{3}= 4 + 4 = 8 ΩThis 8 ohms is in parallel with R

_{2}and can be named as R_{d }Thus,

1/R

_{d }= (1/8) + (1/R_{2}) = (1/8) + (1/8)R

_{d}= 4 ΩR

_{d }is in series with R_{1}Thus,

R

_{eq}= R_{d}+ R_{1}= 4 + 6 = 10 Ω### Answered by Shiwani Sawant | 19th Oct, 2020, 02:45: PM

## Application Videos

## Concept Videos

- Find the equivalent resistance between AB AC and AD
- Q. Find the current drawn from the battery by the network of 4 resistors shown in the diagram. Kindly Refer the file uploaded for diagram.
- please tell how to solve
- what is effective resisitance and how can we find it
- two lamps one rated 100w at 220 v and the other rated 200w at 220v are connected in 1.series 2. parallel to electirc main supplt of 220v. find the current drawn in each case
- Two lamps rated (100w, 220v) and (60w, 220v) are connected in parallel. which lamp consumes more energy and which one gives more brightness? Find the resistance of each lamp. ( Take supply voltage as 220 v).
- Find the equivalent resistance across wire A and B
- Is potential difference between different points of the circuit same or different
- Series combination proportional to its

### Kindly Sign up for a personalised experience

- Ask Study Doubts
- Sample Papers
- Past Year Papers
- Textbook Solutions

#### Sign Up

#### Verify mobile number

Enter the OTP sent to your number

Change