How much maximum amount of Alumininum metal is deposited at cathode by passing one ampere current for 96500seconds through molten AlCl3?
 

Asked by sourabh7jain | 14th Jun, 2016, 11:57: AM

Expert Answer:

Given:
c = 1 ampere
t = 96500 seconds
 
To find: Weight of Al deposited = ?
begin mathsize 12px style Solution colon straight e space equals space fraction numerator 27 over denominator 3 space cross times space 96500 end fraction Weight space of space Al space deposited space equals space equals space fraction numerator 27 space cross times space 1 space cross times space 96500 over denominator 3 space cross times space 96500 end fraction space equals space 9 space gm end style

Answered by Vaibhav Chavan | 15th Jun, 2016, 10:56: AM

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