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CBSE Class 12-science Answered

<div class="title active" style="margin: 0px 0px 10px; padding: 0px; border: 0px; outline: 0px; font-size: 14px; vertical-align: baseline; color: #0081cd; font-stretch: normal; line-height: 14px; font-family: Lato, Arial, Helvetica, sans-serif; width: 549px; background: 0px 0px #f4f7fb;"><a style="margin: 0px 0px 10px; padding: 0px; direction: ltr; unicode-bidi: embed; border: 0px; outline: 0px; vertical-align: baseline; color: #666666 !important; background: 0px 0px;"> <div style="margin: 0px; padding: 0px; border: 0px; outline: 0px; vertical-align: baseline; background: 0px 0px;">How much maximum amount of Alumininum metal is deposited at cathode by passing one ampere current for 96500seconds through molten AlCl3?</div> </a></div> <div class="ansc" style="margin: 0px; padding: 0px; border: 0px; outline: 0px; font-size: 14px; vertical-align: baseline; color: #666666; font-stretch: normal; line-height: 14px; font-family: Lato, Arial, Helvetica, sans-serif; background: 0px 0px #f4f7fb;">&nbsp;</div>
Asked by sourabh7jain | 14 Jun, 2016, 11:57: AM
Expert Answer
Given:
c = 1 ampere
t = 96500 seconds
 
To find: Weight of Al deposited = ?
begin mathsize 12px style Solution colon straight e space equals space fraction numerator 27 over denominator 3 space cross times space 96500 end fraction Weight space of space Al space deposited space equals space equals space fraction numerator 27 space cross times space 1 space cross times space 96500 over denominator 3 space cross times space 96500 end fraction space equals space 9 space gm end style
Answered by Vaibhav Chavan | 15 Jun, 2016, 10:56: AM
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