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CBSE Class 12-science Answered

Can you upload notes on a nernst equations explanation
Asked by keerthana.d.cst.2022 | 22 Aug, 2023, 08:18: PM
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Dear Student,
 
Please follow below link for your answer:
 
Nernst equation
 
Notes on Electrochemistry 
Answered by | 24 Aug, 2023, 10:33: AM

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CBSE 12-science - Chemistry
Can you upload notes on a nernst equations explanation
Asked by keerthana.d.cst.2022 | 22 Aug, 2023, 08:18: PM
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CBSE 12-science - Chemistry
Q. 6. Calculate the emf of the following cell at 298 K Cr(s)/Cr³+ (0.1M)//Fe²+ (0.01M)/Fe(s) [Given: Eºcell = + 0.30 V]
Asked by amankumar2004112 | 04 May, 2022, 01:12: PM
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CBSE 12-science - Chemistry
Please answer this question.
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Asked by Balbir | 02 Oct, 2019, 12:29: AM
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CBSE 12-science - Chemistry
For what concentration of Ag+ will the EMF of te given cell be zero at 25 C .If the concentration of Cu2+ is 0.1 M. EoAg+ = 0.80v and Eo Cu2+ = 0.34 V
Asked by Jsiajaijiaia | 27 Aug, 2019, 12:23: AM
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CBSE 12-science - Chemistry
Please answer. 
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Asked by prakriti12oct | 14 Aug, 2019, 12:46: AM
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CBSE 12-science - Chemistry
Electrochemistry What's 'n' in the equation:           E°(cell) = 0.0591/n log Kc  
Asked by rakeshraghav33 | 19 May, 2018, 03:55: PM
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CBSE 12-science - Chemistry
Predict whether the following redox reaction is feasible under the standard conditions or not.              Sn2+(aq) + Cu(s) →   Sn(s) + Cu2+(aq)
Asked by Topperlearning User | 22 Jun, 2016, 02:42: PM
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CBSE 12-science - Chemistry
Zn(s) | Zn2+(0.01M) || Pb2+(1.OM)|Pb(s) Given: Eo Pb2+/Pb = -0.12V and Eo Zn2+/Zn = -0.76V, what is the cell potential of the cell?
Asked by Topperlearning User | 22 Jun, 2016, 02:41: PM
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CBSE 12-science - Chemistry
Calculate the reduction potential for the following half cell reaction at 298 K.             Ag+(aq) + e- →  Ag(s) Given that   (Ag+) = )0.1M and E° = + 0.80V
Asked by Topperlearning User | 22 Jun, 2016, 02:41: PM
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CBSE 12-science - Chemistry
Calculate EMF of the following cell at 298 K             Ni(s) ½ Ni2+(0.01M) ½½ Ag+(0.1M) ½Ag(s)
Asked by Topperlearning User | 04 Jun, 2014, 01:23: PM
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