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CBSE Class 12-science Answered

Q. 6. Calculate the emf of the following cell at 298 K Cr(s)/Cr³+ (0.1M)//Fe²+ (0.01M)/Fe(s) [Given: Eºcell = + 0.30 V]
Asked by amankumar2004112 | 04 May, 2022, 01:12: PM
answered-by-expert Expert Answer
2Cr(s) + 3Fe2+(aq) → 3Fe(s) + 2Cr3+(aq.)     
 
Number of electrons involved, n = 6
 
straight E blank subscript cell space equals space straight E subscript cel superscript 0 space space minus space fraction numerator 2.303 over denominator nF end fraction space log open square brackets open parentheses Cr to the power of 3 plus end exponent close parentheses squared over open parentheses Fe to the power of 2 plus end exponent close parentheses cubed close square brackets space space space space space space space space space space space space space equals space 0.30 minus fraction numerator 0.059 over denominator 6 end fraction space log open parentheses 10 to the power of negative 1 end exponent close parentheses squared over open parentheses 10 to the power of negative 2 end exponent close parentheses cubed space space space space space space space space space space space space space space space space space space space space space space space space space equals space 0.26 space straight V
Answered by Ramandeep | 04 May, 2022, 01:27: PM

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