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Calculate the reduction potential for the following half cell reaction at 298 K.             Ag+(aq) + e- →  Ag(s) Given that   (Ag+) = )0.1M and E° = + 0.80V
Asked by Topperlearning User | 22 Jun, 2016, 02:41: PM
answered-by-expert Expert Answer
EAg+|Ag = E0Ag+|Ag – ( 2.303 RT / n F ) log10 [Ag] / [Ag+]
                                    = 0.80 – (0.059)/ 1 log10 1 / 0.1 = 0.80 – 0.059 = 0.741V
Answered by | 22 Jun, 2016, 04:41: PM

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Calculate the reduction potential for the following half cell reaction at 298 K.             Ag+(aq) + e- →  Ag(s) Given that   (Ag+) = )0.1M and E° = + 0.80V
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ANSWERED BY EXPERT ANSWERED BY EXPERT
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