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From the diagram, determine i) the equivalent resistance of the entire circuit ii) the current through each resistor iii) th total currnt from the power supply iv) the voltage drop across each resistor PLEASE REPLY AS SOON AS POSSIBLE
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Asked by piyushmalik024 | 18 May, 2019, 10:12: AM
answered-by-expert Expert Answer
i) The resistors R2 and R4 are in series and R3 is connected in parallel to these resistors. 
Thus,
Rs = R2 + R4 = 15 + 15 = 30 Ω
 
1 over R subscript p equals space 1 over R subscript s plus 1 over R subscript 3 space fraction numerator begin display style 1 end style over denominator begin display style R subscript p end style end fraction equals 1 over 30 plus 1 over 20 space T h u s comma space R subscript p space equals space 12 space capital omega  
 
Thus, 
Effective resistance 
Requivalent  = 12 + 20 + 8 = 40 Ω 
 
Thus, equivalent resistance of circuit = 40 Ω 
 
iii) Total current through circuit,
 
V = I R 
 
Total resistance = 40 Ω
Total potential difference = 12 V 
Thus,
I = V/R 
I = 12/40 = 0.3 A 
 
Thus, total current through circuit = 0.3 A 
 
iii) Current across each resistor:
 
The current across R3 = 20 Ω resistor is,
I = V/R = 3.6 / 20 =0.18 A 
 
The current across R2 and R4 = 15 Ω resistor is,
I = 0.3 - 0.18 = 0.12 A 
Current through R1=20 Ω and R5 = 8 Ω is 0.3 A. 
 
 
iv) Voltage across each resistor, 

The voltage drop across R1= 20 Ω,
V = 0.3 x 20 = 6 V
 
Voltage across R5 = 8 Ω resistors is, 
V = 0.3 x 8 = 2.4 V 
 
Voltage drop across combination of R2, R3 and R4
 
V = 0.3 x 12 = 3.6 V
 
Thus, voltage across R3 is 3.6 V.
 
Voltage aross R2 and R4 individually will be, 
V = 0.12 x 15 =  1.8 V 
 
Answered by Shiwani Sawant | 18 May, 2019, 12:52: PM

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