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From the diagram, determine i) the equivalent resistance of the entire circuit ii) the current through each resistor iii) th total currnt from the power supply iv) the voltage drop across each resistor PLEASE REPLY AS SOON AS POSSIBLE
Asked by piyushmalik024 | 18 May, 2019, 10:12: AM
i) The resistors R2 and R4 are in series and R3 is connected in parallel to these resistors.
Thus,
Rs = R2 + R4 = 15 + 15 = 30 Ω

Thus,
Effective resistance
Requivalent  = 12 + 20 + 8 = 40 Ω

Thus, equivalent resistance of circuit = 40 Ω

iii) Total current through circuit,

V = I R

Total resistance = 40 Ω
Total potential difference = 12 V
Thus,
I = V/R
I = 12/40 = 0.3 A

Thus, total current through circuit = 0.3 A

iii) Current across each resistor:

The current across R3 = 20 Ω resistor is,
I = V/R = 3.6 / 20 =0.18 A

The current across R2 and R4 = 15 Ω resistor is,
I = 0.3 - 0.18 = 0.12 A
Current through R1=20 Ω and R5 = 8 Ω is 0.3 A.

iv) Voltage across each resistor,

The voltage drop across R1= 20 Ω,
V = 0.3 x 20 = 6 V

Voltage across R5 = 8 Ω resistors is,
V = 0.3 x 8 = 2.4 V

Voltage drop across combination of R2, R3 and R4

V = 0.3 x 12 = 3.6 V

Thus, voltage across R3 is 3.6 V.

Voltage aross R2 and R4 individually will be,
V = 0.12 x 15 =  1.8 V

Answered by Shiwani Sawant | 18 May, 2019, 12:52: PM

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