for what values of p and q the following system of equations will have infinite solutions 2x+3y=7 and (p-q)x(2 p-q)y=21

Asked by LakshmiSriram | 4th May, 2013, 04:52: PM

Expert Answer:

Please note that there is a typing mistake in the second equation. It should be (p-q)x + (2 p-q)y=21 instead of (p-q)x(2 p-q)y=21. 
So, for infinite solutions
2/p-q = 3/2p-q = 7/21
Hence, p-q = 6
2p-q = 9
Solving simultaneously, p = 3
q = -3

Answered by  | 4th May, 2013, 09:35: PM

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