for what values of p and q the following system of equations will have infinite solutions 2x+3y=7 and (p-q)x(2 p-q)y=21
Asked by LakshmiSriram
| 4th May, 2013,
04:52: PM
Expert Answer:
Please note that there is a typing mistake in the second equation. It should be (p-q)x + (2 p-q)y=21 instead of (p-q)x(2 p-q)y=21.
So, for infinite solutions
2/p-q = 3/2p-q = 7/21
Hence, p-q = 6
2p-q = 9
Solving simultaneously, p = 3
q = -3
Answered by
| 4th May, 2013,
09:35: PM
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