five years hence father's age will be three times his son's age then , five years ago father's age was seven times his son's age then find their present ages

Asked by Prajyot Tugaonkar | 22nd Oct, 2013, 10:51: AM

Expert Answer:

Let the father's age be x and the son's age be y
 
Five years hence:
Father's age = x+5
Son's age = y+5
Given: x+5 = 3(y+5)
That is x - 3y = 10   ....(1)
 
Five years ago:
Father's age = x - 5
Son's age = y - 5
Given: x - 5 = 7(y - 5)
That is x - 7y = -30   ....(2)
 
Solving the two simultaneous equations we have
x = 40 and y = 10
 
Thus the present ages of father and son are 40 and 10

Answered by Vimala Ramamurthy | 22nd Oct, 2013, 12:02: PM

Queries asked on Sunday & after 7pm from Monday to Saturday will be answered after 12pm the next working day.