Findout the dimensions of a,b and c 
 
v=at+b/t+c

Asked by chayanikakashyap1999 | 14th Sep, 2015, 08:57: PM

Expert Answer:

Here v is the velocity and t is the time.
The dimensions of at = Dimensions of velocity v
begin mathsize 14px style therefore left square bracket straight a right square bracket left square bracket straight T right square bracket equals LT to the power of negative 1 end exponent left square bracket straight a right square bracket equals LT to the power of negative 1 end exponent over straight T equals left square bracket LT to the power of negative 2 end exponent right square bracket end style
Dimensions of begin mathsize 14px style fraction numerator straight b over denominator straight t plus straight c end fraction end style = Dimensions of velocity v
                            begin mathsize 14px style equals Displacement over Time end style 
begin mathsize 14px style therefore left square bracket straight b right square bracket left square bracket straight T right square bracket equals left square bracket LT to the power of negative 1 end exponent right square bracket left square bracket straight b right square bracket equals Displacement equals left square bracket straight L right square bracket end style
 
Dimensions of t+c=Dimension of time
begin mathsize 14px style therefore left square bracket straight c right square bracket equals left square bracket straight T right square bracket end style
 
Therefore, the dimensions of a is [LT-2],b is [L] and c is [T]. 

Answered by Faiza Lambe | 14th Sep, 2015, 09:38: PM