find the no of aptical active & inactive forms of compound

Asked by rohus442 | 3rd Nov, 2020, 09:31: AM

Expert Answer:

Dear student,
 
Given compound is having plane of symmetry and total number of chiral carbonIf space straight n minus space odd space number space then space optical space isomers space are space calculated space by minus
Total space number space of space opticallly space activee space isomers equals 2 to the power of straight n minus 1 end exponent minus 2 to the power of left parenthesis fraction numerator straight n minus 1 over denominator 2 end fraction right parenthesis end exponent equals 2 to the power of 3 minus 1 end exponent minus 2 to the power of 1 equals 2 squared minus 2 equals 2

Total space number space of space optically space inative space isomers equals space 2 to the power of open parentheses fraction numerator straight n minus 1 over denominator 2 end fraction close parentheses end exponent equals 2 to the power of 1 equals 2
ons=3
so, number of optically active and inactive isomers can be calculated by-

Answered by Ravi | 10th Nov, 2020, 01:47: PM