find the equations of the straight line which make the following angles with the positive x axis in the positive direction and which passes through the points 150 degrees and -2 comments 1

Asked by Jayanthib615 | 31st Aug, 2020, 03:18: PM

Expert Answer:

Equation of a line passing through a point (x1, y1) with slope m is given by
y-y1 = m(x - x1) where m = tan theta, theta being the angle which a line makes with the x-axis
Point space is space left parenthesis negative 2 comma space 1 right parenthesis space and space angle space is space 150 degree
tan space 150 degree space equals space tan open parentheses 180 degree minus 30 degree close parentheses space equals space minus tan space 30 degree space equals space minus fraction numerator 1 over denominator square root of 3 end fraction
The space equation space is
straight y minus 1 equals negative fraction numerator 1 over denominator square root of 3 end fraction open square brackets straight x minus open parentheses negative 2 close parentheses close square brackets
rightwards double arrow square root of 3 straight y minus square root of 3 equals negative straight x minus 2
rightwards double arrow straight x plus square root of 3 straight y minus square root of 3 plus 2 equals 0 space is space the space required space equation space of space straight space line

Answered by Renu Varma | 4th Sep, 2020, 01:06: PM