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CBSE Class 11-science Answered

Find the equation of the line passing through (5, 4) and perpendicular to the line through the points

(3, 7) and (- 4, 8).

Asked by Topperlearning User | 28 Sep, 2017, 10:58: AM
Expert Answer

Slope of line joining the points (3, 7) and (- 4, 8) = fraction numerator size 12px 8 size 12px space size 12px minus size 12px space size 12px 7 over denominator size 12px minus size 12px 4 size 12px space size 12px minus size 12px space size 12px 3 end fraction size 12px equals fraction numerator size 12px minus size 12px 1 over denominator size 12px 7 end fraction

Slope of line which is perpendicular to the line joining the points (3, 7) and (- 4, 8) = 7.

Equation of line passing through (5, 4) and with slope 7 is
            y - 4 = 7 (x - 5)

       y - 4 = 7x - 35   
                                                                                    
        7x - y - 31 = 0.
Answered by | 28 Sep, 2017, 12:58: PM
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