CBSE Class 12-science Answered
Calculate the
Asked by Ujjwal Kumar | 22 Sep, 2010, 07:00: PM
Expert Answer
E= E0 -0.059/n log [Sn+2] [ Zn+2]/[Sn +4]
where n=2
= .89 - 0.059/2 log 0.5*2.0/1.50
= 0.89- 0.059/2 log 0.667
= 0.89 -(-0.05)
= 0.895 V
thus according to the equation if the concentration of Sn=4 is increased then the cell potential will decrease.
Answered by | 23 Sep, 2010, 12:55: AM
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