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Calculate the H of the following reaction, which describes the production of coal gas from carbon, given the steps below. H2O (g) + C (s) CO (g) + H2 (g) Given Steps H2 (g) + 1/2 O2 (g) H2O (g) H = - 242.0 kJ 2CO (g) 2 C (s) + O2 (g) H = + 221.0 kJ
Asked by Topperlearning User | 15 Jun, 2016, 05:35: PM
1) The overall equation is written above.
Note that the H2O (g) is a reactant and in step #1 it is a product. Thus step one needs to be reversed and the sign of the heat changed.
Note that 1 mole of CO (g) is a product in the overall equation, but 2 moles of CO (g) is a reactant in step 2 . Thus step two needs to be reversed, and divided by two.

2) Manipulated equations

 H2O (g) H2 (g) + 1/2 O2 (g) H = + 242.0 kJ C (s) + 1/2 O2 (g) CO (g) H = - 110.5 kJ

 H2O (g) + C (s) + 1/2 O2 (g) 1/2 O2 (g) + H2 (g) + CO (g) H = +131.5 kJ

Substances in bold above are common and therefore are canceled

Net Equation:
 H2O (g) + C (s) H2 (g) + CO (g) H = +131.5 kJ

Answered by | 15 Jun, 2016, 07:35: PM
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