Calculate the amount of KCl must be added to one kilogram of water so as to reduce its freezing point by two Kelvin. For water Kf = 1.86 K Kg mol-1.

Asked by Topperlearning User | 4th Jun, 2014, 01:23: PM

Expert Answer:

ΔTf = i Kf m
ΔTf = i Kf no of moles / mass of solvent
ΔTf = 2 x 1.86 x n /74.5

n= 2 x 74.5 / 2 x 1.86 = 40.05g.

Answered by  | 4th Jun, 2014, 03:23: PM