An acid solution contains 40% acid, what quantity of solution is to be replaced by the acid to make it 50% acid solution?
Asked by rittwik | 13th Sep, 2010, 12:25: PM
Let the amount of acid solution to be replaced is x lit and original solution is 100 lit.
So we replace x lit of acid solution, we have now 100 - x lit of solution.
The acid content is 40 - 0.4x, and we add x lit of acid, hence,
40 - 0.4x + x is the new acid content, but it's now 50%.
40 - 0.4x + x = 50
x = 100/6 lit = 16.6 lit.
16.6 lit of acid solution is to be replaced by the acid.
Answered by | 13th Sep, 2010, 09:40: PM
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