a wooden cube floating on water supports a mass m=0.2kg on its top.when the mass is removed,the cube rises by 2cm.what is the volume of wooden cube and its each side?
Asked by architsrivastava02 | 13th Dec, 2010, 04:31: PM
The buoyancy force equal to the weight removed springs into action as soon as the mass of 0.2 kg removed.
Buoyancy force = mg = 0.2 kg x 10 m/s2 = 2 N
But this is also given by the weight of water displaced, = Volume displaced x Density x Accln due to gravity.
= 0.02 m x l2 m2 x 1000 kg/m3 x 10 m/s2 = 200l2 N .. where l is side of the cube.
Equating this to 2N.
200l2 = 2 N
l = 10 cm. and V = volume = 1000 cm3.
Answered by | 15th Jan, 2011, 01:13: PM
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